本文实例讲述了ajax实现文件异步上传并回显文件相关信息功能。分享给大家供大家参考，具体如下：

上传文件的信息

<div class="form-group">
 <div class="col-sm-4">
 <label class="control-label">应用文件</label>
</div>
<div class="col-sm-8">
 <input type="file" name="appFile" id="appFile">
 <input type="submit" value="确认上传" id="subm">
</div>

ajax提交

$("#subm").click(function(){
 var formData = new FormData();
 formData.append("appFile", document.getElementById("appFile").files[0]);
 alert("8888888888888888888888888");
 $.ajax({
 url: '${ctx}/appresources/fileUpload.shtml',
 type: "POST",
 data: formData,
 dataType: "json",
 contentType: false,
 processData: false,
 success: function (data) {
 alert("上传成功");
 $("#versionCode").val(data.versionCode);
 $("#appVersion").val(data.appVersion);
 $("#appPackageName").val(data.appPackageName);
 },
 error: function () {
 alert("上传失败！");
 }
 });
});

后台处理：

@ResponseBody
@RequestMapping("fileUpload")
public JSONObject fileUpload(MultipartFile appFile,Model model,HttpServletRequest request,HttpServletResponse response) {
 ServletContext
//........................省略
 String infos=ApkUtil.getApkInfo(needPath+"source"+File.separator+"apk"+File.separator+fileName);
 String[] info=infos.split(",");
 String versionCode=info[0];//版本号
 String versionName=info[1];//版本名
 String packageName=info[2];//包名
 String appName=fileName;
 AppResourcesFormMap appResourcesFormMap = getFormMap(AppResourcesFormMap.class);
 appResourcesFormMap.put("appName",fileName);
 appResourcesFormMap.put("appVersion",versionName);
 appResourcesFormMap.put("appPackageName",packageName);
 appResourcesFormMap.put("versionCode", versionCode);
 System.out.println(appResourcesFormMap);
 //model.addAttribute("appresources", appResourcesFormMap);
 JSONObject fromObject = JSONObject.fromObject(appResourcesFormMap);
 //String string = fromObject.toString();
 return fromObject;
}

更多关于ajax相关内容感兴趣的读者可查看本站专题：《jquery中Ajax用法总结》、《JavaScript中ajax操作技巧总结》、《PHP+ajax技巧与应用小结》及《asp.net ajax技巧总结专题》

希望本文所述对大家ajax程序设计有所帮助。