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如何去掉数据库重复记录并且只保留一条记录
2020-11-09 16:03:51 责编:小采
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在n条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复并保留一条呢? 方法如下: 1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 select * from peoplewhere peopleId in (select peopleId from people group by peopleId hav

在n条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复并保留一条呢?

方法如下:


1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断


select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)

2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录


delete from people 
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)

3、查找表中多余的重复记录(多个字段)

select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)

4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录


delete from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)


5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录


select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

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