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CodeforcesRound#273(Div.2)AInitialBet_html/css
2020-11-27 15:56:36 责编:小采
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题目链接:Initial Bet


Initial Bet


time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

There are five people playing a game called "Generosity". Each person gives some non-zero number of coins b as an initial bet. After all players make their bets of b coins, the following operation is repeated for several times: a coin is passed from one player to some other player.

Your task is to write a program that can, given the number of coins each player has at the end of the game, determine the size b of the initial bet or find out that such outcome of the game cannot be obtained for any positive number of coins b in the initial bet.

Input

The input consists of a single line containing five integers c1,?c2,?c3,?c4 and c5 ? the number of coins that the first, second, third, fourth and fifth players respectively have at the end of the game (0?≤?c1,?c2,?c3,?c4,?c5?≤?100).

Output

Print the only line containing a single positive integer b ? the number of coins in the initial bet of each player. If there is no such value of b, then print the only value "-1" (quotes for clarity).

Sample test(s)

input

2 5 4 0 4

output

input

4 5 9 2 1

output

-1

Note

In the first sample the following sequence of operations is possible:

  1. One coin is passed from the fourth player to the second player;
  2. One coin is passed from the fourth player to the fifth player;
  3. One coin is passed from the first player to the third player;
  4. One coin is passed from the fourth player to the second player.




解题思路:水题,不解释,8分钟交题,虽然一激动少了个条件,忘记判非零了,但是还是在10分钟内出了这题,创了我的cf最快出题纪录了~~~




AC代码:

#include #include #include #include #include #include #include #include #include #include #include #include using namespace std;#define INF 0x7fffffffint main(){ #ifdef sxk freopen("in.txt","r",stdin); #endif int a,b,c,d,e; while(scanf("%d%d%d%d%d",&a,&b,&c,&d,&e)!=EOF) { int sum = a + b + c + d + e; if(sum%5 == 0 && sum) printf("%d\n", sum/5); else printf("%d\n", -1); } return 0;}

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